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» Welcome to Pocket Bike Racing

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  #21 (permalink)  
Old 09-02-2010, 09:44 AM
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A: The one I put in PBOTM, Oct i think!! But these days it is only 39cc with one piece head. Gives the other guys over here half a chance lol

Q: Who thinks TyD should "sponsor" me his cag for "the Bool" weekend???
Back on topic!!!!
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Old 09-02-2010, 10:04 AM
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A. Nah, he can't he needs the money!! But he should!!

Q. Who thinks ty should get a better paying job than workin at nudgee maccas?!??!?

maybe you could ask boyracer for a loan... lol
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  #23 (permalink)  
Old 09-02-2010, 11:01 AM
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A: Yeah TyD get a loan off boyracerr and bring the cag. I'll show you how to ride it properly for FREE!!!!!

Q: We have got three definites from WA and maybe a fourth.
How many guys are coming from QLD?
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Old 09-02-2010, 11:51 AM
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A. thats great ringo... there will be 3 atm from QLD.

Liam-Gray & Me.. .. 4 if you count Bill...hehe

Q. How far behind Morty will Mago be?!??! hahaha
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Old 09-02-2010, 01:36 PM
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A: If it's 12 lap races then probz about 11 laps behind you, he still seems scared of the throttle lol..

Q: Who thinks Morty should take me down to kick some little china bike butt? Free of charge of course

and yes I do need a better paying job..
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, ill tell ya 1 thing tho , if your close to the archiefield track and you dont go , your mad ,bloody top effort and ill let you in on a lil secret ,there BLOODY FAST ,so you need bigg balls
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Old 09-02-2010, 01:58 PM
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A: Morty should bring you and boyracerr down and a spare cag for me. I here his cags are some of the best in the land!!

Q: Who reckons TyD and boyracerr should have a drinking comp with each other in "the bool"?
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  #27 (permalink)  
Old 09-02-2010, 02:11 PM
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A: Yeah, I think I would drink BoyRacerr under the table..... Morty should take me, and then I could sponsor you with a cag to ride around on..

Q: Who thinks Ringo Should just Bring his own cag? lol.. Or Buy mine at bool?
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TEAM GMR - When Appearence Matters
★ 140cc Mini Motard - Billetware frame, Billetware swingarm QLD #3
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Quote:
Originally Posted by SnItChY View Post
, ill tell ya 1 thing tho , if your close to the archiefield track and you dont go , your mad ,bloody top effort and ill let you in on a lil secret ,there BLOODY FAST ,so you need bigg balls
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  #28 (permalink)  
Old 09-02-2010, 04:01 PM
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A: I think you should keep you cag and ride it ffs

Q: Where is the weirdest place you have a mole?
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Old 09-02-2010, 05:10 PM
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A: on my johnson

Q: what is the square root of a negative number?
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  #30 (permalink)  
Old 09-02-2010, 06:22 PM
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A: Here you go smart a**

As you no doubt know, a square root is a number that when multiplied
by itself is equal to a given number. For example, 4 is the square
root of 16, since 4 x 4 = 16. Note, however, that -4 x -4 = 16, too.
We call 4 the positive square root of 16, and -4 the negative square
root of 16.

Now, you want to know if we can find the square root of a negative
number. Let's take -16. We need to find a number, call it x, such
that:
x times x (x^2) = -16

Now, we know that any number times itself must be positive, not
negative. Therefore, there is no such number x in the set of real
numbers.

A number x is defined, however, in the set of complex numbers. The
complex numbers are a superset of the real numbers. That is, the
complex numbers form a bigger set. The reals are a subset of the
complex.

A complex number has the form a + bi, where a and b are real numbers
and the i is a special number. The "a" is called the real part; the
"bi" is called the imaginary part. If we let a equal 0, then we have
an imaginary number. The set of imaginary numbers is also a subset of
the complex numbers. If we let b equal 0, then we have a regular real
number. This is why the reals are a subset of the complex: the reals
are just complex numbers that all have b=0, that is, no imaginary
part.

Now, the number i is defined to be equal to the square root of -1.
This means that i^2 (i squared) is equal to -1. So now we can find
the square root of -16.

Since -16 = (-1) 16, we can write:

sqr(-16) = sqr(-1) times sqr(16) (property of square roots)
sqr(-16) = i times 4

This is usually written as 4i. We can check by squaring 4i. We get
4 x 4 = 16 times i x i = sqr(-1) times sqr(-1) = -1, giving 16 times
-1 or -16.


Q: Who's pi**ed that I'm goin ridin' tonight (6-9 flood-lit) at Cockburn WA?
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